8[3-(2-3x)]+4x=4(7x+3)-4

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Solution for 8[3-(2-3x)]+4x=4(7x+3)-4 equation: 


Simplifying
8[3 + -1(2 + -3x)] + 4x = 4(7x + 3) + -4
8[3 + (2 * -1 + -3x * -1)] + 4x = 4(7x + 3) + -4
8[3 + (-2 + 3x)] + 4x = 4(7x + 3) + -4

Combine like terms: 3 + -2 = 1
8[1 + 3x] + 4x = 4(7x + 3) + -4
[1 * 8 + 3x * 8] + 4x = 4(7x + 3) + -4
[8 + 24x] + 4x = 4(7x + 3) + -4

Combine like terms: 24x + 4x = 28x
8 + 28x = 4(7x + 3) + -4

Reorder the terms:
8 + 28x = 4(3 + 7x) + -4
8 + 28x = (3 * 4 + 7x * 4) + -4
8 + 28x = (12 + 28x) + -4

Reorder the terms:
8 + 28x = 12 + -4 + 28x

Combine like terms: 12 + -4 = 8
8 + 28x = 8 + 28x

Add '-8' to each side of the equation.
8 + -8 + 28x = 8 + -8 + 28x

Combine like terms: 8 + -8 = 0
0 + 28x = 8 + -8 + 28x
28x = 8 + -8 + 28x

Combine like terms: 8 + -8 = 0
28x = 0 + 28x
28x = 28x

Add '-28x' to each side of the equation.
28x + -28x = 28x + -28x

Combine like terms: 28x + -28x = 0
0 = 28x + -28x

Combine like terms: 28x + -28x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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